Solve for b a=bc+ba

$a = b c + b a$

Rewrite the equation as $b c + b a = a$ .

$b c + b a = a$

Factor $b$ out of $b c + b a$ .

Factor $b$ out of $b c$ .

$b (c) + b a = a$

Factor $b$ out of $b a$ .

$b (c) + b (a) = a$

Factor $b$ out of $b (c) + b (a)$ .

$b (c + a) = a$

Divide each term in $b (c + a) = a$ by $c + a$ and simplify.

Divide each term in $b (c + a) = a$ by $c + a$ .

$\frac{b (c + a)}{c + a} = \frac{a}{c + a}$

Simplify the left side.

Cancel the common factor of $c + a$ .

Cancel the common factor.

$\frac{b (c + a)}{c + a} = \frac{a}{c + a}$

Divide $b$ by $1$ .

$b = \frac{a}{c + a}$