Solve for b ab-2=3c

$a b - 2 = 3 c$

Add $2$ to both sides of the equation.

$a b = 3 c + 2$

Divide each term in $a b = 3 c + 2$ by $a$ and simplify.

Divide each term in $a b = 3 c + 2$ by $a$ .

$\frac{a b}{a} = \frac{3 c}{a} + \frac{2}{a}$

Simplify the left side.

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a b}{a} = \frac{3 c}{a} + \frac{2}{a}$

Divide $b$ by $1$ .

$b = \frac{3 c}{a} + \frac{2}{a}$