Solve for b ab+3c=2x

$a b + 3 c = 2 x$

Step 1

Subtract $3 c$ from both sides of the equation.

$a b = 2 x - 3 c$

Step 2

Divide each term in $a b = 2 x - 3 c$ by $a$ and simplify.

Divide each term in $a b = 2 x - 3 c$ by $a$ .

$\frac{a b}{a} = \frac{2 x}{a} + \frac{- 3 c}{a}$

Simplify the left side.

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a b}{a} = \frac{2 x}{a} + \frac{- 3 c}{a}$

Divide $b$ by $1$ .

$b = \frac{2 x}{a} + \frac{- 3 c}{a}$

Simplify the right side.

Move the negative in front of the fraction.

$b = \frac{2 x}{a} - \frac{3 c}{a}$