Solve for b b^2=-3b

$b^{2} = - 3 b$

Step 1

Add $3 b$ to both sides of the equation.

$b^{2} + 3 b = 0$

Step 2

Factor $b$ out of $b^{2} + 3 b$ .

Factor $b$ out of $b^{2}$ .

$b \cdot b + 3 b = 0$

Factor $b$ out of $3 b$ .

$b \cdot b + b \cdot 3 = 0$

Factor $b$ out of $b \cdot b + b \cdot 3$ .

$b (b + 3) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$b = 0$

$b + 3 = 0$

Step 4

Set $b$ equal to $0$ .

$b = 0$

Step 5

Set $b + 3$ equal to $0$ and solve for $b$ .

Set $b + 3$ equal to $0$ .

$b + 3 = 0$

Subtract $3$ from both sides of the equation.

$b = - 3$

Step 6

The final solution is all the values that make $b (b + 3) = 0$ true.

$b = 0, - 3$