Solve for B B^2-6=5 an

$B^{2} - 6 = 5$ an

Move all terms not containing $B$ to the right side of the equation.

Add $6$ to both sides of the equation.

$B^{2} = 5 + 6$

Add $5$ and $6$ .

$B^{2} = 11$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$B = \pm \sqrt{11}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$B = \sqrt{11}$

Next, use the negative value of the $\pm$ to find the second solution.

$B = - \sqrt{11}$

The complete solution is the result of both the positive and negative portions of the solution.

$B = \sqrt{11}, - \sqrt{11}$

The result can be shown in multiple forms.

Exact Form:

$B = \sqrt{11}, - \sqrt{11}$

Decimal Form:

$B = 3.31662479 \dots, - 3.31662479 \dots$