Solve for b (b^2)^a=b^8

${(b^{2})}^{a} = b^{8}$

Step 1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$b^{2 a} = b^{8}$

Step 2

Subtract $b^{8}$ from both sides of the equation.

$b^{2 a} - b^{8} = 0$