Solve for b b+5<=9b-4

$b + 5 \leq 9 b - 4$

Move all terms containing $b$ to the left side of the inequality.

Subtract $9 b$ from both sides of the inequality.

$b + 5 - 9 b \leq - 4$

Subtract $9 b$ from $b$ .

$- 8 b + 5 \leq - 4$

Move all terms not containing $b$ to the right side of the inequality.

Subtract $5$ from both sides of the inequality.

$- 8 b \leq - 4 - 5$

Subtract $5$ from $- 4$ .

$- 8 b \leq - 9$

Divide each term in $- 8 b \leq - 9$ by $- 8$ and simplify.

Divide each term in $- 8 b \leq - 9$ by $- 8$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 8 b}{- 8} \geq \frac{- 9}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 b}{- 8} \geq \frac{- 9}{- 8}$

Divide $b$ by $1$ .

$b \geq \frac{- 9}{- 8}$

Simplify the right side.

Dividing two negative values results in a positive value.

$b \geq \frac{9}{8}$

The result can be shown in multiple forms.

Inequality Form:

$b \geq \frac{9}{8}$

Interval Notation:

$[\frac{9}{8}, \infty)$

Solve for b b+5<=9b-4

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