Solve for B f(B-g^3)=2

$f (B - g^{3}) = 2$

Step 1

Divide each term in $f (B - g^{3}) = 2$ by $f$ and simplify.

Divide each term in $f (B - g^{3}) = 2$ by $f$ .

$\frac{f (B - g^{3})}{f} = \frac{2}{f}$

Simplify the left side.

Cancel the common factor of $f$ .

Cancel the common factor.

$\frac{f (B - g^{3})}{f} = \frac{2}{f}$

Divide $B - g^{3}$ by $1$ .

$B - g^{3} = \frac{2}{f}$

Step 2

Add $g^{3}$ to both sides of the equation.

$B = \frac{2}{f} + g^{3}$