Solve for B F(B-g^3)=2

$F (B - g^{3}) = 2$

Divide each term in $F (B - g^{3}) = 2$ by $F$ and simplify.

Divide each term in $F (B - g^{3}) = 2$ by $F$ .

$\frac{F (B - g^{3})}{F} = \frac{2}{F}$

Simplify the left side.

Cancel the common factor of $F$ .

Cancel the common factor.

$\frac{F (B - g^{3})}{F} = \frac{2}{F}$

Divide $B - g^{3}$ by $1$ .

$B - g^{3} = \frac{2}{F}$

Add $g^{3}$ to both sides of the equation.

$B = \frac{2}{F} + g^{3}$