Solve for b gb+Nb=2F^2

$g b + N b = 2 F^{2}$

Step 1

Factor $b$ out of $g b + N b$ .

Factor $b$ out of $g b$ .

$b g + N b = 2 F^{2}$

Factor $b$ out of $N b$ .

$b g + b N = 2 F^{2}$

Factor $b$ out of $b g + b N$ .

$b (g + N) = 2 F^{2}$

Step 2

Divide each term in $b (g + N) = 2 F^{2}$ by $g + N$ and simplify.

Divide each term in $b (g + N) = 2 F^{2}$ by $g + N$ .

$\frac{b (g + N)}{g + N} = \frac{2 F^{2}}{g + N}$

Simplify the left side.

Cancel the common factor of $g + N$ .

Cancel the common factor.

$\frac{b (g + N)}{g + N} = \frac{2 F^{2}}{g + N}$

Divide $b$ by $1$ .

$b = \frac{2 F^{2}}{g + N}$