Solve for B h=D^2(B-5g)

$h = D^{2} (B - 5 g)$

Rewrite the equation as $D^{2} (B - 5 g) = h$ .

$D^{2} (B - 5 g) = h$

Divide each term in $D^{2} (B - 5 g) = h$ by $D^{2}$ and simplify.

Divide each term in $D^{2} (B - 5 g) = h$ by $D^{2}$ .

$\frac{D^{2} (B - 5 g)}{D^{2}} = \frac{h}{D^{2}}$

Simplify the left side.

Cancel the common factor of $D^{2}$ .

Cancel the common factor.

$\frac{D^{2} (B - 5 g)}{D^{2}} = \frac{h}{D^{2}}$

Divide $B - 5 g$ by $1$ .

$B - 5 g = \frac{h}{D^{2}}$

Add $5 g$ to both sides of the equation.

$B = \frac{h}{D^{2}} + 5 g$