Solve for B R=4(B-A)

$R = 4 (B - A)$

Rewrite the equation as $4 (B - A) = R$ .

$4 (B - A) = R$

Divide each term in $4 (B - A) = R$ by $4$ and simplify.

Divide each term in $4 (B - A) = R$ by $4$ .

$\frac{4 (B - A)}{4} = \frac{R}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (B - A)}{4} = \frac{R}{4}$

Divide $B - A$ by $1$ .

$B - A = \frac{R}{4}$

Add $A$ to both sides of the equation.

$B = \frac{R}{4} + A$