Solve for b r=(b-a)m

$r = (b - a) m$

Rewrite the equation as $(b - a) m = r$ .

$(b - a) m = r$

Divide each term in $(b - a) m = r$ by $m$ and simplify.

Divide each term in $(b - a) m = r$ by $m$ .

$\frac{(b - a) m}{m} = \frac{r}{m}$

Simplify the left side.

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{(b - a) m}{m} = \frac{r}{m}$

Divide $b - a$ by $1$ .

$b - a = \frac{r}{m}$

Add $a$ to both sides of the equation.

$b = \frac{r}{m} + a$