Solve for b s=ph+2b

$s = p h + 2 b$

Rewrite the equation as $p h + 2 b = s$ .

$p h + 2 b = s$

Subtract $p h$ from both sides of the equation.

$2 b = s - p h$

Divide each term in $2 b = s - p h$ by $2$ and simplify.

Divide each term in $2 b = s - p h$ by $2$ .

$\frac{2 b}{2} = \frac{s}{2} + \frac{- p h}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 b}{2} = \frac{s}{2} + \frac{- p h}{2}$

Divide $b$ by $1$ .

$b = \frac{s}{2} + \frac{- p h}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$b = \frac{s}{2} - \frac{p h}{2}$