Solve for c 0.5+3(5c-0.7)=13c

$0.5 + 3 (5 c - 0.7) = 13 c$

Step 1

Simplify $0.5 + 3 (5 c - 0.7)$ .

Simplify each term.

Apply the distributive property.

$0.5 + 3 (5 c) + 3 \cdot - 0.7 = 13 c$

Multiply $5$ by $3$ .

$0.5 + 15 c + 3 \cdot - 0.7 = 13 c$

Multiply $3$ by $- 0.7$ .

$0.5 + 15 c - 2.1 = 13 c$

Subtract $2.1$ from $0.5$ .

$15 c - 1.6 = 13 c$

Step 2

Move all terms containing $c$ to the left side of the equation.

Subtract $13 c$ from both sides of the equation.

$15 c - 1.6 - 13 c = 0$

Subtract $13 c$ from $15 c$ .

$2 c - 1.6 = 0$

Step 3

Add $1.6$ to both sides of the equation.

$2 c = 1.6$

Step 4

Divide each term in $2 c = 1.6$ by $2$ and simplify.

Divide each term in $2 c = 1.6$ by $2$ .

$\frac{2 c}{2} = \frac{1.6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 c}{2} = \frac{1.6}{2}$

Divide $c$ by $1$ .

$c = \frac{1.6}{2}$

Simplify the right side.

Divide $1.6$ by $2$ .

$c = 0.8$