Solve for c 1/2c=-3-3/2c-5/2c+1

$\frac{1}{2} c = - 3 - \frac{3}{2} c - \frac{5}{2} c + 1$

Since $c$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 3 - \frac{3}{2} c - \frac{5}{2} c + 1 = \frac{1}{2} c$

Simplify $- 3 - \frac{3}{2} c - \frac{5}{2} c + 1$ .

Simplify each term.

Combine $c$ and $\frac{3}{2}$ .

$- 3 - \frac{c \cdot 3}{2} - \frac{5}{2} c + 1 = \frac{1}{2} c$

Move $3$ to the left of $c$ .

$- 3 - \frac{3 \cdot c}{2} - \frac{5}{2} c + 1 = \frac{1}{2} c$

Combine $c$ and $\frac{5}{2}$ .

$- 3 - \frac{3 c}{2} - \frac{c \cdot 5}{2} + 1 = \frac{1}{2} c$

Move $5$ to the left of $c$ .

$- 3 - \frac{3 c}{2} - \frac{5 c}{2} + 1 = \frac{1}{2} c$

Simplify terms.

Combine the numerators over the common denominator.

$- 3 + 1 + \frac{- 3 c - 5 c}{2} = \frac{1}{2} c$

Subtract $5 c$ from $- 3 c$ .

$- 3 + 1 + \frac{- 8 c}{2} = \frac{1}{2} c$

Cancel the common factor of $- 8$ and $2$ .

Factor $2$ out of $- 8 c$ .

$- 3 + 1 + \frac{2 (- 4 c)}{2} = \frac{1}{2} c$

Cancel the common factors.

Factor $2$ out of $2$ .

$- 3 + 1 + \frac{2 (- 4 c)}{2 (1)} = \frac{1}{2} c$

Cancel the common factor.

$- 3 + 1 + \frac{2 (- 4 c)}{2 \cdot 1} = \frac{1}{2} c$

Rewrite the expression.

$- 3 + 1 + \frac{- 4 c}{1} = \frac{1}{2} c$

Divide $- 4 c$ by $1$ .

$- 3 + 1 - 4 c = \frac{1}{2} c$

Add $- 3$ and $1$ .

$- 2 - 4 c = \frac{1}{2} c$

Combine $\frac{1}{2}$ and $c$ .

$- 2 - 4 c = \frac{c}{2}$

Move all terms containing $c$ to the left side of the equation.

Subtract $\frac{c}{2}$ from both sides of the equation.

$- 2 - 4 c - \frac{c}{2} = 0$

To write $- 4 c$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- 2 - 4 c \cdot \frac{2}{2} - \frac{c}{2} = 0$

Combine $- 4 c$ and $\frac{2}{2}$ .

$- 2 + \frac{- 4 c \cdot 2}{2} - \frac{c}{2} = 0$

Combine the numerators over the common denominator.

$- 2 + \frac{- 4 c \cdot 2 - c}{2} = 0$

Simplify each term.

Simplify the numerator.

Factor $c$ out of $- 4 c \cdot 2 - c$ .

Factor $c$ out of $- 4 c \cdot 2$ .

$- 2 + \frac{c (- 4 \cdot 2) - c}{2} = 0$

Factor $c$ out of $- c$ .

$- 2 + \frac{c (- 4 \cdot 2) + c \cdot - 1}{2} = 0$

Factor $c$ out of $c (- 4 \cdot 2) + c \cdot - 1$ .

$- 2 + \frac{c (- 4 \cdot 2 - 1)}{2} = 0$

Multiply $- 4$ by $2$ .

$- 2 + \frac{c (- 8 - 1)}{2} = 0$

Subtract $1$ from $- 8$ .

$- 2 + \frac{c \cdot - 9}{2} = 0$

Move $- 9$ to the left of $c$ .

$- 2 + \frac{- 9 \cdot c}{2} = 0$

Move the negative in front of the fraction.

$- 2 - \frac{9 c}{2} = 0$

Add $2$ to both sides of the equation.

$- \frac{9 c}{2} = 2$

Multiply both sides of the equation by $- \frac{2}{9}$ .

$- \frac{2}{9} (- \frac{9 c}{2}) = - \frac{2}{9} \cdot 2$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{2}{9} (- \frac{9 c}{2})$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{2}{9}$ into the numerator.

$\frac{- 2}{9} (- \frac{9 c}{2}) = - \frac{2}{9} \cdot 2$

Move the leading negative in $- \frac{9 c}{2}$ into the numerator.

$\frac{- 2}{9} \cdot \frac{- 9 c}{2} = - \frac{2}{9} \cdot 2$

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{9} \cdot \frac{- 9 c}{2} = - \frac{2}{9} \cdot 2$

Cancel the common factor.

$\frac{2 \cdot - 1}{9} \cdot \frac{- 9 c}{2} = - \frac{2}{9} \cdot 2$

Rewrite the expression.

$\frac{- 1}{9} (- 9 c) = - \frac{2}{9} \cdot 2$

Cancel the common factor of $9$ .

Factor $9$ out of $- 9 c$ .

$\frac{- 1}{9} (9 (- c)) = - \frac{2}{9} \cdot 2$

Cancel the common factor.

$\frac{- 1}{9} (9 (- c)) = - \frac{2}{9} \cdot 2$

Rewrite the expression.

$- - c = - \frac{2}{9} \cdot 2$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 c = - \frac{2}{9} \cdot 2$

Multiply $c$ by $1$ .

$c = - \frac{2}{9} \cdot 2$

Simplify the right side.

Simplify $- \frac{2}{9} \cdot 2$ .

Multiply $- \frac{2}{9} \cdot 2$ .

Multiply $2$ by $- 1$ .

$c = - 2 (\frac{2}{9})$

Combine $- 2$ and $\frac{2}{9}$ .

$c = \frac{- 2 \cdot 2}{9}$

Multiply $- 2$ by $2$ .

$c = \frac{- 4}{9}$

Move the negative in front of the fraction.

$c = - \frac{4}{9}$

The result can be shown in multiple forms.

Exact Form:

$c = - \frac{4}{9}$

Decimal Form:

$c = - 0.\overline{4}$

Solve for c 1/2c=-3-3/2c-5/2c+1

Related Questions

Support LCMGCF.com by disabling your adblocker.