Solve for c 1+3c=5(1-c)+8c

$1 + 3 c = 5 (1 - c) + 8 c$

Since $c$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$5 (1 - c) + 8 c = 1 + 3 c$

Simplify $5 (1 - c) + 8 c$ .

Simplify each term.

Apply the distributive property.

$5 \cdot 1 + 5 (- c) + 8 c = 1 + 3 c$

Multiply $5$ by $1$ .

$5 + 5 (- c) + 8 c = 1 + 3 c$

Multiply $- 1$ by $5$ .

$5 - 5 c + 8 c = 1 + 3 c$

Add $- 5 c$ and $8 c$ .

$5 + 3 c = 1 + 3 c$

Move all terms containing $c$ to the left side of the equation.

Subtract $3 c$ from both sides of the equation.

$5 + 3 c - 3 c = 1$

Combine the opposite terms in $5 + 3 c - 3 c$ .

Subtract $3 c$ from $3 c$ .

$5 + 0 = 1$

Add $5$ and $0$ .

$5 = 1$

Since $5 \neq 1$ , there are no solutions.

No solution