Solve for c 10c+7>=5c+5

$10 c + 7 \geq 5 c + 5$

Step 1

Move all terms containing $c$ to the left side of the inequality.

Subtract $5 c$ from both sides of the inequality.

$10 c + 7 - 5 c \geq 5$

Subtract $5 c$ from $10 c$ .

$5 c + 7 \geq 5$

Step 2

Move all terms not containing $c$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$5 c \geq 5 - 7$

Subtract $7$ from $5$ .

$5 c \geq - 2$

Step 3

Divide each term in $5 c \geq - 2$ by $5$ and simplify.

Divide each term in $5 c \geq - 2$ by $5$ .

$\frac{5 c}{5} \geq \frac{- 2}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 c}{5} \geq \frac{- 2}{5}$

Divide $c$ by $1$ .

$c \geq \frac{- 2}{5}$

Simplify the right side.

Move the negative in front of the fraction.

$c \geq - \frac{2}{5}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$c \geq - \frac{2}{5}$

Interval Notation:

$[- \frac{2}{5}, \infty)$