Solve for c 12+1/5(10c+5)=59

$12 + \frac{1}{5} (10 c + 5) = 59$

Simplify $12 + \frac{1}{5} \cdot (10 c + 5)$ .

Simplify each term.

Apply the distributive property.

$12 + \frac{1}{5} (10 c) + \frac{1}{5} \cdot 5 = 59$

Cancel the common factor of $5$ .

Factor $5$ out of $10 c$ .

$12 + \frac{1}{5} (5 (2 c)) + \frac{1}{5} \cdot 5 = 59$

Cancel the common factor.

$12 + \frac{1}{5} (5 (2 c)) + \frac{1}{5} \cdot 5 = 59$

Rewrite the expression.

$12 + 2 c + \frac{1}{5} \cdot 5 = 59$

Cancel the common factor of $5$ .

Cancel the common factor.

$12 + 2 c + \frac{1}{5} \cdot 5 = 59$

Rewrite the expression.

$12 + 2 c + 1 = 59$

Add $12$ and $1$ .

$2 c + 13 = 59$

Move all terms not containing $c$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$2 c = 59 - 13$

Subtract $13$ from $59$ .

$2 c = 46$

Divide each term in $2 c = 46$ by $2$ and simplify.

Divide each term in $2 c = 46$ by $2$ .

$\frac{2 c}{2} = \frac{46}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 c}{2} = \frac{46}{2}$

Divide $c$ by $1$ .

$c = \frac{46}{2}$

Simplify the right side.

Divide $46$ by $2$ .

$c = 23$