Solve for c 12=|-3c+3|

$12 = | - 3 c + 3 |$

Rewrite the equation as $| - 3 c + 3 | = 12$ .

$| - 3 c + 3 | = 12$

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$- 3 c + 3 = \pm 12$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$- 3 c + 3 = 12$

Move all terms not containing $c$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 3 c = 12 - 3$

Subtract $3$ from $12$ .

$- 3 c = 9$

Divide each term in $- 3 c = 9$ by $- 3$ and simplify.

Divide each term in $- 3 c = 9$ by $- 3$ .

$\frac{- 3 c}{- 3} = \frac{9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 c}{- 3} = \frac{9}{- 3}$

Divide $c$ by $1$ .

$c = \frac{9}{- 3}$

Simplify the right side.

Divide $9$ by $- 3$ .

$c = - 3$

Next, use the negative value of the $\pm$ to find the second solution.

$- 3 c + 3 = - 12$

Move all terms not containing $c$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 3 c = - 12 - 3$

Subtract $3$ from $- 12$ .

$- 3 c = - 15$

Divide each term in $- 3 c = - 15$ by $- 3$ and simplify.

Divide each term in $- 3 c = - 15$ by $- 3$ .

$\frac{- 3 c}{- 3} = \frac{- 15}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 c}{- 3} = \frac{- 15}{- 3}$

Divide $c$ by $1$ .

$c = \frac{- 15}{- 3}$

Simplify the right side.

Divide $- 15$ by $- 3$ .

$c = 5$

The complete solution is the result of both the positive and negative portions of the solution.

$c = - 3, 5$

Solve for c 12=|-3c+3|

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