Solve for c 12c-4=14c-10

$12 c - 4 = 14 c - 10$

Move all terms containing $c$ to the left side of the equation.

Subtract $14 c$ from both sides of the equation.

$12 c - 4 - 14 c = - 10$

Subtract $14 c$ from $12 c$ .

$- 2 c - 4 = - 10$

Move all terms not containing $c$ to the right side of the equation.

Add $4$ to both sides of the equation.

$- 2 c = - 10 + 4$

Add $- 10$ and $4$ .

$- 2 c = - 6$

Divide each term in $- 2 c = - 6$ by $- 2$ and simplify.

Divide each term in $- 2 c = - 6$ by $- 2$ .

$\frac{- 2 c}{- 2} = \frac{- 6}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 c}{- 2} = \frac{- 6}{- 2}$

Divide $c$ by $1$ .

$c = \frac{- 6}{- 2}$

Simplify the right side.

Divide $- 6$ by $- 2$ .

$c = 3$