Solve for c -13c+12c+3c-4=-18

$- 13 c + 12 c + 3 c - 4 = - 18$

Simplify $- 13 c + 12 c + 3 c - 4$ .

Add $- 13 c$ and $12 c$ .

$- c + 3 c - 4 = - 18$

Add $- c$ and $3 c$ .

$2 c - 4 = - 18$

Move all terms not containing $c$ to the right side of the equation.

Add $4$ to both sides of the equation.

$2 c = - 18 + 4$

Add $- 18$ and $4$ .

$2 c = - 14$

Divide each term in $2 c = - 14$ by $2$ and simplify.

Divide each term in $2 c = - 14$ by $2$ .

$\frac{2 c}{2} = \frac{- 14}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 c}{2} = \frac{- 14}{2}$

Divide $c$ by $1$ .

$c = \frac{- 14}{2}$

Simplify the right side.

Divide $- 14$ by $2$ .

$c = - 7$