Solve for c 13c-3c+6c=48

$13 c - 3 c + 6 c = 48$

Simplify $13 c - 3 c + 6 c$ .

Subtract $3 c$ from $13 c$ .

$10 c + 6 c = 48$

Add $10 c$ and $6 c$ .

$16 c = 48$

Divide each term in $16 c = 48$ by $16$ and simplify.

Divide each term in $16 c = 48$ by $16$ .

$\frac{16 c}{16} = \frac{48}{16}$

Simplify the left side.

Cancel the common factor of $16$ .

Cancel the common factor.

$\frac{16 c}{16} = \frac{48}{16}$

Divide $c$ by $1$ .

$c = \frac{48}{16}$

Simplify the right side.

Divide $48$ by $16$ .

$c = 3$