Solve for c 2+c+11=-c-19

$2 + c + 11 = - c - 19$

Step 1

Add $2$ and $11$ .

$c + 13 = - c - 19$

Step 2

Move all terms containing $c$ to the left side of the equation.

Add $c$ to both sides of the equation.

$c + 13 + c = - 19$

Add $c$ and $c$ .

$2 c + 13 = - 19$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$2 c = - 19 - 13$

Subtract $13$ from $- 19$ .

$2 c = - 32$

Step 4

Divide each term in $2 c = - 32$ by $2$ and simplify.

Divide each term in $2 c = - 32$ by $2$ .

$\frac{2 c}{2} = \frac{- 32}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 c}{2} = \frac{- 32}{2}$

Divide $c$ by $1$ .

$c = \frac{- 32}{2}$

Simplify the right side.

Divide $- 32$ by $2$ .

$c = - 16$