Solve for c -20+18c=6c+14+10c

$- 20 + 18 c = 6 c + 14 + 10 c$

Step 1

Since $c$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$6 c + 14 + 10 c = - 20 + 18 c$

Step 2

Add $6 c$ and $10 c$ .

$16 c + 14 = - 20 + 18 c$

Step 3

Move all terms containing $c$ to the left side of the equation.

Subtract $18 c$ from both sides of the equation.

$16 c + 14 - 18 c = - 20$

Subtract $18 c$ from $16 c$ .

$- 2 c + 14 = - 20$

Step 4

Move all terms not containing $c$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$- 2 c = - 20 - 14$

Subtract $14$ from $- 20$ .

$- 2 c = - 34$

Step 5

Divide each term in $- 2 c = - 34$ by $- 2$ and simplify.

Divide each term in $- 2 c = - 34$ by $- 2$ .

$\frac{- 2 c}{- 2} = \frac{- 34}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 c}{- 2} = \frac{- 34}{- 2}$

Divide $c$ by $1$ .

$c = \frac{- 34}{- 2}$

Simplify the right side.

Divide $- 34$ by $- 2$ .

$c = 17$