Solve for c -20-4c-6c=2(9c+19)-2

$- 20 - 4 c - 6 c = 2 (9 c + 19) - 2$

Subtract $6 c$ from $- 4 c$ .

$- 20 - 10 c = 2 (9 c + 19) - 2$

Simplify $2 (9 c + 19) - 2$ .

Simplify each term.

Apply the distributive property.

$- 20 - 10 c = 2 (9 c) + 2 \cdot 19 - 2$

Multiply $9$ by $2$ .

$- 20 - 10 c = 18 c + 2 \cdot 19 - 2$

Multiply $2$ by $19$ .

$- 20 - 10 c = 18 c + 38 - 2$

Subtract $2$ from $38$ .

$- 20 - 10 c = 18 c + 36$

Move all terms containing $c$ to the left side of the equation.

Subtract $18 c$ from both sides of the equation.

$- 20 - 10 c - 18 c = 36$

Subtract $18 c$ from $- 10 c$ .

$- 20 - 28 c = 36$

Move all terms not containing $c$ to the right side of the equation.

Add $20$ to both sides of the equation.

$- 28 c = 36 + 20$

Add $36$ and $20$ .

$- 28 c = 56$

Divide each term in $- 28 c = 56$ by $- 28$ and simplify.

Divide each term in $- 28 c = 56$ by $- 28$ .

$\frac{- 28 c}{- 28} = \frac{56}{- 28}$

Simplify the left side.

Cancel the common factor of $- 28$ .

Cancel the common factor.

$\frac{- 28 c}{- 28} = \frac{56}{- 28}$

Divide $c$ by $1$ .

$c = \frac{56}{- 28}$

Simplify the right side.

Divide $56$ by $- 28$ .

$c = - 2$