Solve for c 2c-12c+13c=12

$2 c - 12 c + 13 c = 12$

Step 1

Simplify $2 c - 12 c + 13 c$ .

Subtract $12 c$ from $2 c$ .

$- 10 c + 13 c = 12$

Add $- 10 c$ and $13 c$ .

$3 c = 12$

Step 2

Divide each term in $3 c = 12$ by $3$ and simplify.

Divide each term in $3 c = 12$ by $3$ .

$\frac{3 c}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 c}{3} = \frac{12}{3}$

Divide $c$ by $1$ .

$c = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$c = 4$