Solve for c 2c-4=3(4-2c)

$2 c - 4 = 3 (4 - 2 c)$

Step 1

Simplify $3 (4 - 2 c)$ .

Rewrite.

$2 c - 4 = 0 + 0 + 3 (4 - 2 c)$

Simplify by adding zeros.

$2 c - 4 = 3 (4 - 2 c)$

Apply the distributive property.

$2 c - 4 = 3 \cdot 4 + 3 (- 2 c)$

Multiply.

Multiply $3$ by $4$ .

$2 c - 4 = 12 + 3 (- 2 c)$

Multiply $- 2$ by $3$ .

$2 c - 4 = 12 - 6 c$

Step 2

Move all terms containing $c$ to the left side of the equation.

Add $6 c$ to both sides of the equation.

$2 c - 4 + 6 c = 12$

Add $2 c$ and $6 c$ .

$8 c - 4 = 12$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Add $4$ to both sides of the equation.

$8 c = 12 + 4$

Add $12$ and $4$ .

$8 c = 16$

Step 4

Divide each term in $8 c = 16$ by $8$ and simplify.

Divide each term in $8 c = 16$ by $8$ .

$\frac{8 c}{8} = \frac{16}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 c}{8} = \frac{16}{8}$

Divide $c$ by $1$ .

$c = \frac{16}{8}$

Simplify the right side.

Divide $16$ by $8$ .

$c = 2$