Solve for c 2c-4=(4-2c)

$2 c - 4 = (4 - 2 c)$

Step 1

Move all terms containing $c$ to the left side of the equation.

Add $2 c$ to both sides of the equation.

$2 c - 4 + 2 c = 4$

Add $2 c$ and $2 c$ .

$4 c - 4 = 4$

Step 2

Move all terms not containing $c$ to the right side of the equation.

Add $4$ to both sides of the equation.

$4 c = 4 + 4$

Add $4$ and $4$ .

$4 c = 8$

Step 3

Divide each term in $4 c = 8$ by $4$ and simplify.

Divide each term in $4 c = 8$ by $4$ .

$\frac{4 c}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 c}{4} = \frac{8}{4}$

Divide $c$ by $1$ .

$c = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$c = 2$