Solve for c 2x^3-8x^2-24x=ax(x+b)(x+c)

$2 x^{3} - 8 x^{2} - 24 x = a x (x + b) (x + c)$

Rewrite the equation as $a x (x + b) (x + c) = 2 x^{3} - 8 x^{2} - 24 x$ .

$a x (x + b) (x + c) = 2 x^{3} - 8 x^{2} - 24 x$

Divide each term in $a x (x + b) (x + c) = 2 x^{3} - 8 x^{2} - 24 x$ by $a x (x + b)$ and simplify.

Divide each term in $a x (x + b) (x + c) = 2 x^{3} - 8 x^{2} - 24 x$ by $a x (x + b)$ .

$\frac{a x (x + b) (x + c)}{a x (x + b)} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Simplify the left side.

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a x (x + b) (x + c)}{a x (x + b)} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Rewrite the expression.

$\frac{(x (x + b)) (x + c)}{x (x + b)} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x (x + b) (x + c)}{x (x + b)} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Rewrite the expression.

$\frac{(x + b) (x + c)}{x + b} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor of $x + b$ .

Cancel the common factor.

$\frac{(x + b) (x + c)}{x + b} = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Divide $x + c$ by $1$ .

$x + c = \frac{2 x^{3}}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $x^{3}$ and $x$ .

Factor $x$ out of $2 x^{3}$ .

$x + c = \frac{x (2 x^{2})}{a x (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factors.

Factor $x$ out of $a x (x + b)$ .

$x + c = \frac{x (2 x^{2})}{x (a (x + b))} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor.

$x + c = \frac{x (2 x^{2})}{x (a (x + b))} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Rewrite the expression.

$x + c = \frac{2 x^{2}}{a (x + b)} + \frac{- 8 x^{2}}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor of $x^{2}$ and $x$ .

Factor $x$ out of $- 8 x^{2}$ .

$x + c = \frac{2 x^{2}}{a (x + b)} + \frac{x (- 8 x)}{a x (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factors.

Factor $x$ out of $a x (x + b)$ .

$x + c = \frac{2 x^{2}}{a (x + b)} + \frac{x (- 8 x)}{x (a (x + b))} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor.

$x + c = \frac{2 x^{2}}{a (x + b)} + \frac{x (- 8 x)}{x (a (x + b))} + \frac{- 24 x}{a x (x + b)}$

Rewrite the expression.

$x + c = \frac{2 x^{2}}{a (x + b)} + \frac{- 8 x}{a (x + b)} + \frac{- 24 x}{a x (x + b)}$

Move the negative in front of the fraction.

$x + c = \frac{2 x^{2}}{a (x + b)} - \frac{(8) x}{a (x + b)} + \frac{- 24 x}{a x (x + b)}$

Cancel the common factor of $x$ .

Cancel the common factor.

$x + c = \frac{2 x^{2}}{a (x + b)} - \frac{8 x}{a (x + b)} + \frac{- 24 x}{a x (x + b)}$

Rewrite the expression.

$x + c = \frac{2 x^{2}}{a (x + b)} - \frac{8 x}{a (x + b)} + \frac{- 24}{a (x + b)}$

Move the negative in front of the fraction.

$x + c = \frac{2 x^{2}}{a (x + b)} - \frac{8 x}{a (x + b)} - \frac{24}{a (x + b)}$

Subtract $x$ from both sides of the equation.

$c = \frac{2 x^{2}}{a (x + b)} - \frac{8 x}{a (x + b)} - \frac{24}{a (x + b)} - x$

Solve for c 2x^3-8x^2-24x=ax(x+b)(x+c)

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