Solve for c -3=-15-2(c-1)-3c

$- 3 = - 15 - 2 (c - 1) - 3 c$

Rewrite the equation as $- 15 - 2 (c - 1) - 3 c = - 3$ .

$- 15 - 2 (c - 1) - 3 c = - 3$

Simplify $- 15 - 2 (c - 1) - 3 c$ .

Simplify each term.

Apply the distributive property.

$- 15 - 2 c - 2 \cdot - 1 - 3 c = - 3$

Multiply $- 2$ by $- 1$ .

$- 15 - 2 c + 2 - 3 c = - 3$

Simplify by adding terms.

Add $- 15$ and $2$ .

$- 2 c - 13 - 3 c = - 3$

Subtract $3 c$ from $- 2 c$ .

$- 5 c - 13 = - 3$

Move all terms not containing $c$ to the right side of the equation.

Add $13$ to both sides of the equation.

$- 5 c = - 3 + 13$

Add $- 3$ and $13$ .

$- 5 c = 10$

Divide each term in $- 5 c = 10$ by $- 5$ and simplify.

Divide each term in $- 5 c = 10$ by $- 5$ .

$\frac{- 5 c}{- 5} = \frac{10}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 c}{- 5} = \frac{10}{- 5}$

Divide $c$ by $1$ .

$c = \frac{10}{- 5}$

Simplify the right side.

Divide $10$ by $- 5$ .

$c = - 2$