Solve for c 3-15c=-12c+2-17

$3 - 15 c = - 12 c + 2 - 17$

Step 1

Subtract $17$ from $2$ .

$3 - 15 c = - 12 c - 15$

Step 2

Move all terms containing $c$ to the left side of the equation.

Add $12 c$ to both sides of the equation.

$3 - 15 c + 12 c = - 15$

Add $- 15 c$ and $12 c$ .

$3 - 3 c = - 15$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 3 c = - 15 - 3$

Subtract $3$ from $- 15$ .

$- 3 c = - 18$

Step 4

Divide each term in $- 3 c = - 18$ by $- 3$ and simplify.

Divide each term in $- 3 c = - 18$ by $- 3$ .

$\frac{- 3 c}{- 3} = \frac{- 18}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 c}{- 3} = \frac{- 18}{- 3}$

Divide $c$ by $1$ .

$c = \frac{- 18}{- 3}$

Simplify the right side.

Divide $- 18$ by $- 3$ .

$c = 6$