Solve for c -3(3c+5)=2(10-c)

$- 3 (3 c + 5) = 2 (10 - c)$

Simplify $- 3 (3 c + 5)$ .

Start simplifying.

$0 + 0 - 3 (3 c + 5) = 2 (10 - c)$

Simplify by adding zeros.

$- 3 (3 c + 5) = 2 (10 - c)$

Apply the distributive property.

$- 3 (3 c) - 3 \cdot 5 = 2 (10 - c)$

Multiply.

Multiply $3$ by $- 3$ .

$- 9 c - 3 \cdot 5 = 2 (10 - c)$

Multiply $- 3$ by $5$ .

$- 9 c - 15 = 2 (10 - c)$

Simplify $2 (10 - c)$ .

Apply the distributive property.

$- 9 c - 15 = 2 \cdot 10 + 2 (- c)$

Multiply.

Multiply $2$ by $10$ .

$- 9 c - 15 = 20 + 2 (- c)$

Multiply $- 1$ by $2$ .

$- 9 c - 15 = 20 - 2 c$

Move all terms containing $c$ to the left side of the equation.

Add $2 c$ to both sides of the equation.

$- 9 c - 15 + 2 c = 20$

Add $- 9 c$ and $2 c$ .

$- 7 c - 15 = 20$

Move all terms not containing $c$ to the right side of the equation.

Add $15$ to both sides of the equation.

$- 7 c = 20 + 15$

Add $20$ and $15$ .

$- 7 c = 35$

Divide each term in $- 7 c = 35$ by $- 7$ and simplify.

Divide each term in $- 7 c = 35$ by $- 7$ .

$\frac{- 7 c}{- 7} = \frac{35}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 c}{- 7} = \frac{35}{- 7}$

Divide $c$ by $1$ .

$c = \frac{35}{- 7}$

Simplify the right side.

Divide $35$ by $- 7$ .

$c = - 5$