Solve for c 3(cx-7)=9

$3 (c x - 7) = 9$

Step 1

Divide each term in $3 (c x - 7) = 9$ by $3$ and simplify.

Divide each term in $3 (c x - 7) = 9$ by $3$ .

$\frac{3 (c x - 7)}{3} = \frac{9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (c x - 7)}{3} = \frac{9}{3}$

Divide $c x - 7$ by $1$ .

$c x - 7 = \frac{9}{3}$

Simplify the right side.

Divide $9$ by $3$ .

$c x - 7 = 3$

Step 2

Move all terms not containing $c$ to the right side of the equation.

Add $7$ to both sides of the equation.

$c x = 3 + 7$

Add $3$ and $7$ .

$c x = 10$

Step 3

Divide each term in $c x = 10$ by $x$ and simplify.

Divide each term in $c x = 10$ by $x$ .

$\frac{c x}{x} = \frac{10}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{c x}{x} = \frac{10}{x}$

Divide $c$ by $1$ .

$c = \frac{10}{x}$