Solve for c 4c-20=-20+4c

$4 c - 20 = - 20 + 4 c$

Move all terms containing $c$ to the left side of the equation.

Subtract $4 c$ from both sides of the equation.

$4 c - 20 - 4 c = - 20$

Combine the opposite terms in $4 c - 20 - 4 c$ .

Subtract $4 c$ from $4 c$ .

$0 - 20 = - 20$

Subtract $20$ from $0$ .

$- 20 = - 20$

Since $- 20 = - 20$ , the equation will always be true for any value of $c$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$