Solve for c 5c-4-2c+1=8c+2

$5 c - 4 - 2 c + 1 = 8 c + 2$

Step 1

Simplify $5 c - 4 - 2 c + 1$ .

Subtract $2 c$ from $5 c$ .

$3 c - 4 + 1 = 8 c + 2$

Add $- 4$ and $1$ .

$3 c - 3 = 8 c + 2$

Step 2

Move all terms containing $c$ to the left side of the equation.

Subtract $8 c$ from both sides of the equation.

$3 c - 3 - 8 c = 2$

Subtract $8 c$ from $3 c$ .

$- 5 c - 3 = 2$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- 5 c = 2 + 3$

Add $2$ and $3$ .

$- 5 c = 5$

Step 4

Divide each term in $- 5 c = 5$ by $- 5$ and simplify.

Divide each term in $- 5 c = 5$ by $- 5$ .

$\frac{- 5 c}{- 5} = \frac{5}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 c}{- 5} = \frac{5}{- 5}$

Divide $c$ by $1$ .

$c = \frac{5}{- 5}$

Simplify the right side.

Divide $5$ by $- 5$ .

$c = - 1$