Solve for c 5c-5=-5c-7

$5 c - 5 = - 5 c - 7$

Move all terms containing $c$ to the left side of the equation.

Add $5 c$ to both sides of the equation.

$5 c - 5 + 5 c = - 7$

Add $5 c$ and $5 c$ .

$10 c - 5 = - 7$

Move all terms not containing $c$ to the right side of the equation.

Add $5$ to both sides of the equation.

$10 c = - 7 + 5$

Add $- 7$ and $5$ .

$10 c = - 2$

Divide each term in $10 c = - 2$ by $10$ and simplify.

Divide each term in $10 c = - 2$ by $10$ .

$\frac{10 c}{10} = \frac{- 2}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 c}{10} = \frac{- 2}{10}$

Divide $c$ by $1$ .

$c = \frac{- 2}{10}$

Simplify the right side.

Cancel the common factor of $- 2$ and $10$ .

Factor $2$ out of $- 2$ .

$c = \frac{2 (- 1)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$c = \frac{2 \cdot - 1}{2 \cdot 5}$

Cancel the common factor.

$c = \frac{2 \cdot - 1}{2 \cdot 5}$

Rewrite the expression.

$c = \frac{- 1}{5}$

Move the negative in front of the fraction.

$c = - \frac{1}{5}$

The result can be shown in multiple forms.

Exact Form:

$c = - \frac{1}{5}$

Decimal Form:

$c = - 0.2$