Solve for c -5c+6=1/3c-26

$- 5 c + 6 = \frac{1}{3} c - 26$

Combine $\frac{1}{3}$ and $c$ .

$- 5 c + 6 = \frac{c}{3} - 26$

Move all terms containing $c$ to the left side of the equation.

Subtract $\frac{c}{3}$ from both sides of the equation.

$- 5 c + 6 - \frac{c}{3} = - 26$

To write $- 5 c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- 5 c \cdot \frac{3}{3} - \frac{c}{3} + 6 = - 26$

Combine $- 5 c$ and $\frac{3}{3}$ .

$\frac{- 5 c \cdot 3}{3} - \frac{c}{3} + 6 = - 26$

Combine the numerators over the common denominator.

$\frac{- 5 c \cdot 3 - c}{3} + 6 = - 26$

Simplify each term.

Simplify the numerator.

Factor $c$ out of $- 5 c \cdot 3 - c$ .

Factor $c$ out of $- 5 c \cdot 3$ .

$\frac{c (- 5 \cdot 3) - c}{3} + 6 = - 26$

Factor $c$ out of $- c$ .

$\frac{c (- 5 \cdot 3) + c \cdot - 1}{3} + 6 = - 26$

Factor $c$ out of $c (- 5 \cdot 3) + c \cdot - 1$ .

$\frac{c (- 5 \cdot 3 - 1)}{3} + 6 = - 26$

Multiply $- 5$ by $3$ .

$\frac{c (- 15 - 1)}{3} + 6 = - 26$

Subtract $1$ from $- 15$ .

$\frac{c \cdot - 16}{3} + 6 = - 26$

Move $- 16$ to the left of $c$ .

$\frac{- 16 \cdot c}{3} + 6 = - 26$

Move the negative in front of the fraction.

$- \frac{16 c}{3} + 6 = - 26$

Move all terms not containing $c$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$- \frac{16 c}{3} = - 26 - 6$

Subtract $6$ from $- 26$ .

$- \frac{16 c}{3} = - 32$

Multiply both sides of the equation by $- \frac{3}{16}$ .

$- \frac{3}{16} (- \frac{16 c}{3}) = - \frac{3}{16} \cdot - 32$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{16} (- \frac{16 c}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{16}$ into the numerator.

$\frac{- 3}{16} (- \frac{16 c}{3}) = - \frac{3}{16} \cdot - 32$

Move the leading negative in $- \frac{16 c}{3}$ into the numerator.

$\frac{- 3}{16} \cdot \frac{- 16 c}{3} = - \frac{3}{16} \cdot - 32$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{16} \cdot \frac{- 16 c}{3} = - \frac{3}{16} \cdot - 32$

Cancel the common factor.

$\frac{3 \cdot - 1}{16} \cdot \frac{- 16 c}{3} = - \frac{3}{16} \cdot - 32$

Rewrite the expression.

$\frac{- 1}{16} (- 16 c) = - \frac{3}{16} \cdot - 32$

Cancel the common factor of $16$ .

Factor $16$ out of $- 16 c$ .

$\frac{- 1}{16} (16 (- c)) = - \frac{3}{16} \cdot - 32$

Cancel the common factor.

$\frac{- 1}{16} (16 (- c)) = - \frac{3}{16} \cdot - 32$

Rewrite the expression.

$- - c = - \frac{3}{16} \cdot - 32$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 c = - \frac{3}{16} \cdot - 32$

Multiply $c$ by $1$ .

$c = - \frac{3}{16} \cdot - 32$

Simplify the right side.

Simplify $- \frac{3}{16} \cdot - 32$ .

Cancel the common factor of $16$ .

Move the leading negative in $- \frac{3}{16}$ into the numerator.

$c = \frac{- 3}{16} \cdot - 32$

Factor $16$ out of $- 32$ .

$c = \frac{- 3}{16} \cdot (16 (- 2))$

Cancel the common factor.

$c = \frac{- 3}{16} \cdot (16 \cdot - 2)$

Rewrite the expression.

$c = - 3 \cdot - 2$

Multiply $- 3$ by $- 2$ .

$c = 6$

Solve for c -5c+6=1/3c-26

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