Solve for c 6c+3=c-12

$6 c + 3 = c - 12$

Step 1

Move all terms containing $c$ to the left side of the equation.

Subtract $c$ from both sides of the equation.

$6 c + 3 - c = - 12$

Subtract $c$ from $6 c$ .

$5 c + 3 = - 12$

Step 2

Move all terms not containing $c$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$5 c = - 12 - 3$

Subtract $3$ from $- 12$ .

$5 c = - 15$

Step 3

Divide each term in $5 c = - 15$ by $5$ and simplify.

Divide each term in $5 c = - 15$ by $5$ .

$\frac{5 c}{5} = \frac{- 15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 c}{5} = \frac{- 15}{5}$

Divide $c$ by $1$ .

$c = \frac{- 15}{5}$

Simplify the right side.

Divide $- 15$ by $5$ .

$c = - 3$