Solve for c 8(c+10)=9c

$8 (c + 10) = 9 c$

Simplify $8 (c + 10)$ .

Start simplifying.

$0 + 0 + 8 (c + 10) = 9 c$

Simplify by adding zeros.

$8 (c + 10) = 9 c$

Apply the distributive property.

$8 c + 8 \cdot 10 = 9 c$

Multiply $8$ by $10$ .

$8 c + 80 = 9 c$

Move all terms containing $c$ to the left side of the equation.

Subtract $9 c$ from both sides of the equation.

$8 c + 80 - 9 c = 0$

Subtract $9 c$ from $8 c$ .

$- c + 80 = 0$

Subtract $80$ from both sides of the equation.

$- c = - 80$

Divide each term in $- c = - 80$ by $- 1$ and simplify.

Divide each term in $- c = - 80$ by $- 1$ .

$\frac{- c}{- 1} = \frac{- 80}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{c}{1} = \frac{- 80}{- 1}$

Divide $c$ by $1$ .

$c = \frac{- 80}{- 1}$

Simplify the right side.

Divide $- 80$ by $- 1$ .

$c = 80$