Solve for c 8=c/-4+6

$8 = \frac{c}{- 4} + 6$

Step 1

Rewrite the equation as $\frac{c}{- 4} + 6 = 8$ .

$\frac{c}{- 4} + 6 = 8$

Step 2

Move the negative in front of the fraction.

$- \frac{c}{4} + 6 = 8$

Step 3

Move all terms not containing $c$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$- \frac{c}{4} = 8 - 6$

Subtract $6$ from $8$ .

$- \frac{c}{4} = 2$

Step 4

Multiply both sides of the equation by $- 4$ .

$- 4 (- \frac{c}{4}) = - 4 \cdot 2$

Step 5

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 4 (- \frac{c}{4})$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{c}{4}$ into the numerator.

$- 4 \frac{- c}{4} = - 4 \cdot 2$

Factor $4$ out of $- 4$ .

$4 (- 1) \frac{- c}{4} = - 4 \cdot 2$

Cancel the common factor.

$4 \cdot - 1 \frac{- c}{4} = - 4 \cdot 2$

Rewrite the expression.

$- - c = - 4 \cdot 2$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 c = - 4 \cdot 2$

Multiply $c$ by $1$ .

$c = - 4 \cdot 2$

Simplify the right side.

Multiply $- 4$ by $2$ .

$c = - 8$