Solve for c 9/5c+32=F

$\frac{9}{5} c + 32 = F$

Step 1

Combine $\frac{9}{5}$ and $c$ .

$\frac{9 c}{5} + 32 = F$

Step 2

Subtract $32$ from both sides of the equation.

$\frac{9 c}{5} = F - 32$

Step 3

Multiply both sides of the equation by $\frac{5}{9}$ .

$\frac{5}{9} \cdot \frac{9 c}{5} = \frac{5}{9} (F - 32)$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{9} \cdot \frac{9 c}{5}$ .

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{9} \cdot \frac{9 c}{5} = \frac{5}{9} (F - 32)$

Rewrite the expression.

$\frac{1}{9} (9 c) = \frac{5}{9} (F - 32)$

Cancel the common factor of $9$ .

Factor $9$ out of $9 c$ .

$\frac{1}{9} (9 (c)) = \frac{5}{9} (F - 32)$

Cancel the common factor.

$\frac{1}{9} (9 c) = \frac{5}{9} (F - 32)$

Rewrite the expression.

$c = \frac{5}{9} (F - 32)$

Simplify the right side.

Simplify $\frac{5}{9} (F - 32)$ .

Apply the distributive property.

$c = \frac{5}{9} F + \frac{5}{9} \cdot - 32$

Combine $\frac{5}{9}$ and $F$ .

$c = \frac{5 F}{9} + \frac{5}{9} \cdot - 32$

Multiply $\frac{5}{9} \cdot - 32$ .

Combine $\frac{5}{9}$ and $- 32$ .

$c = \frac{5 F}{9} + \frac{5 \cdot - 32}{9}$

Multiply $5$ by $- 32$ .

$c = \frac{5 F}{9} + \frac{- 160}{9}$

Move the negative in front of the fraction.

$c = \frac{5 F}{9} - \frac{160}{9}$