Solve for c 9c-1<4c-5

$9 c - 1 < 4 c - 5$

Step 1

Move all terms containing $c$ to the left side of the inequality.

Subtract $4 c$ from both sides of the inequality.

$9 c - 1 - 4 c < - 5$

Subtract $4 c$ from $9 c$ .

$5 c - 1 < - 5$

Step 2

Move all terms not containing $c$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$5 c < - 5 + 1$

Add $- 5$ and $1$ .

$5 c < - 4$

Step 3

Divide each term in $5 c < - 4$ by $5$ and simplify.

Divide each term in $5 c < - 4$ by $5$ .

$\frac{5 c}{5} < \frac{- 4}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 c}{5} < \frac{- 4}{5}$

Divide $c$ by $1$ .

$c < \frac{- 4}{5}$

Simplify the right side.

Move the negative in front of the fraction.

$c < - \frac{4}{5}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$c < - \frac{4}{5}$

Interval Notation:

$(- \infty, - \frac{4}{5})$