Solve for c -9c-12+3c=12

$- 9 c - 12 + 3 c = 12$

Step 1

Add $- 9 c$ and $3 c$ .

$- 6 c - 12 = 12$

Step 2

Move all terms not containing $c$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- 6 c = 12 + 12$

Add $12$ and $12$ .

$- 6 c = 24$

Step 3

Divide each term in $- 6 c = 24$ by $- 6$ and simplify.

Divide each term in $- 6 c = 24$ by $- 6$ .

$\frac{- 6 c}{- 6} = \frac{24}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 c}{- 6} = \frac{24}{- 6}$

Divide $c$ by $1$ .

$c = \frac{24}{- 6}$

Simplify the right side.

Divide $24$ by $- 6$ .

$c = - 4$