Solve for c 9x+3=cx+3+4x

$9 x + 3 = c x + 3 + 4 x$

Rewrite the equation as $c x + 3 + 4 x = 9 x + 3$ .

$c x + 3 + 4 x = 9 x + 3$

Move all terms not containing $c$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$c x + 4 x = 9 x + 3 - 3$

Subtract $4 x$ from both sides of the equation.

$c x = 9 x + 3 - 3 - 4 x$

Combine the opposite terms in $9 x + 3 - 3 - 4 x$ .

Subtract $3$ from $3$ .

$c x = 9 x + 0 - 4 x$

Add $9 x$ and $0$ .

$c x = 9 x - 4 x$

Subtract $4 x$ from $9 x$ .

$c x = 5 x$

Divide each term in $c x = 5 x$ by $x$ and simplify.

Divide each term in $c x = 5 x$ by $x$ .

$\frac{c x}{x} = \frac{5 x}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{c x}{x} = \frac{5 x}{x}$

Divide $c$ by $1$ .

$c = \frac{5 x}{x}$

Simplify the right side.

Cancel the common factor of $x$ .

Cancel the common factor.

$c = \frac{5 x}{x}$

Divide $5$ by $1$ .

$c = 5$