Solve for c a=11+4b-4c

$a = 11 + 4 b - 4 c$

Rewrite the equation as $11 + 4 b - 4 c = a$ .

$11 + 4 b - 4 c = a$

Move all terms not containing $c$ to the right side of the equation.

Subtract $11$ from both sides of the equation.

$4 b - 4 c = a - 11$

Subtract $4 b$ from both sides of the equation.

$- 4 c = a - 11 - 4 b$

Divide each term in $- 4 c = a - 11 - 4 b$ by $- 4$ and simplify.

Divide each term in $- 4 c = a - 11 - 4 b$ by $- 4$ .

$\frac{- 4 c}{- 4} = \frac{a}{- 4} + \frac{- 11}{- 4} + \frac{- 4 b}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 c}{- 4} = \frac{a}{- 4} + \frac{- 11}{- 4} + \frac{- 4 b}{- 4}$

Divide $c$ by $1$ .

$c = \frac{a}{- 4} + \frac{- 11}{- 4} + \frac{- 4 b}{- 4}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$c = - \frac{a}{4} + \frac{- 11}{- 4} + \frac{- 4 b}{- 4}$

Dividing two negative values results in a positive value.

$c = - \frac{a}{4} + \frac{11}{4} + \frac{- 4 b}{- 4}$

Cancel the common factor of $- 4$ .

Cancel the common factor.

$c = - \frac{a}{4} + \frac{11}{4} + \frac{- 4 b}{- 4}$

Divide $b$ by $1$ .

$c = - \frac{a}{4} + \frac{11}{4} + b$