Solve for C A=5/6(B+C)

$A = \frac{5}{6} (B + C)$

Rewrite the equation as $\frac{5}{6} \cdot (B + C) = A$ .

$\frac{5}{6} \cdot (B + C) = A$

Multiply both sides of the equation by $\frac{6}{5}$ .

$\frac{6}{5} (\frac{5}{6} \cdot (B + C)) = \frac{6}{5} A$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{6}{5} (\frac{5}{6} \cdot (B + C))$ .

Apply the distributive property.

$\frac{6}{5} (\frac{5}{6} B + \frac{5}{6} C) = \frac{6}{5} A$

Combine $\frac{5}{6}$ and $B$ .

$\frac{6}{5} (\frac{5 B}{6} + \frac{5}{6} C) = \frac{6}{5} A$

Combine $\frac{5}{6}$ and $C$ .

$\frac{6}{5} (\frac{5 B}{6} + \frac{5 C}{6}) = \frac{6}{5} A$

Apply the distributive property.

$\frac{6}{5} \cdot \frac{5 B}{6} + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6}{5} \cdot \frac{5 B}{6} + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Rewrite the expression.

$\frac{1}{5} (5 B) + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Cancel the common factor of $5$ .

Factor $5$ out of $5 B$ .

$\frac{1}{5} (5 (B)) + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Cancel the common factor.

$\frac{1}{5} (5 B) + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Rewrite the expression.

$B + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Cancel the common factor of $6$ .

Cancel the common factor.

$B + \frac{6}{5} \cdot \frac{5 C}{6} = \frac{6}{5} A$

Rewrite the expression.

$B + \frac{1}{5} (5 C) = \frac{6}{5} A$

Cancel the common factor of $5$ .

Factor $5$ out of $5 C$ .

$B + \frac{1}{5} (5 (C)) = \frac{6}{5} A$

Cancel the common factor.

$B + \frac{1}{5} (5 C) = \frac{6}{5} A$

Rewrite the expression.

$B + C = \frac{6}{5} A$

Simplify the right side.

Combine $\frac{6}{5}$ and $A$ .

$B + C = \frac{6 A}{5}$

Subtract $B$ from both sides of the equation.

$C = \frac{6 A}{5} - B$