Solve for c A=(a+b+c)/3

$A = \frac{a + b + c}{3}$

Step 1

Rewrite the equation as $\frac{a + b + c}{3} = A$ .

$\frac{a + b + c}{3} = A$

Step 2

Multiply both sides of the equation by $3$ .

$3 \frac{a + b + c}{3} = 3 A$

Step 3

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$3 \frac{a + b + c}{3} = 3 A$

Rewrite the expression.

$a + b + c = 3 A$

Step 4

Move all terms not containing $c$ to the right side of the equation.

Subtract $a$ from both sides of the equation.

$b + c = 3 A - a$

Subtract $b$ from both sides of the equation.

$c = 3 A - a - b$