Solve for c -(a+b)c=-a-b

$- (a + b) c = - a - b$

Step 1

Apply the distributive property.

$(- a - b) c = - a - b$

Step 2

Divide each term in $(- a - b) c = - a - b$ by $- a - b$ and simplify.

Divide each term in $(- a - b) c = - a - b$ by $- a - b$ .

$\frac{(- a - b) c}{- a - b} = \frac{- a}{- a - b} + \frac{- b}{- a - b}$

Simplify the left side.

Cancel the common factor of $- a - b$ .

Cancel the common factor.

$\frac{(- a - b) c}{- a - b} = \frac{- a}{- a - b} + \frac{- b}{- a - b}$

Divide $c$ by $1$ .

$c = \frac{- a}{- a - b} + \frac{- b}{- a - b}$

Simplify the right side.

Combine the numerators over the common denominator.

$c = \frac{- a - b}{- a - b}$

Cancel the common factor of $- a - b$ .

Cancel the common factor.

$c = \frac{- a - b}{- a - b}$

Rewrite the expression.

$c = 1$