Solve for c ab-c=9

$a b - c = 9$

Step 1

Subtract $a b$ from both sides of the equation.

$- c = 9 - a b$

Step 2

Divide each term in $- c = 9 - a b$ by $- 1$ and simplify.

Divide each term in $- c = 9 - a b$ by $- 1$ .

$\frac{- c}{- 1} = \frac{9}{- 1} + \frac{- a b}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{c}{1} = \frac{9}{- 1} + \frac{- a b}{- 1}$

Divide $c$ by $1$ .

$c = \frac{9}{- 1} + \frac{- a b}{- 1}$

Simplify the right side.

Simplify each term.

Divide $9$ by $- 1$ .

$c = - 9 + \frac{- a b}{- 1}$

Dividing two negative values results in a positive value.

$c = - 9 + \frac{a b}{1}$

Divide $a b$ by $1$ .

$c = - 9 + a b$